Centrifugal Correction to g
Any particle of mass m on the surface of earth (regarded as a uniform sphere of mass Me and Radius Re) is subjected to an acceleration due to gravity given by
which we refer to as the ‘true’ value of g. The gravitational force of interaction between earth and particle is the cause for g : Fg = m g, where g is radially towards the center of earth.
However, when observed from the rotating frame attached to earth, the particle is also subjected to inertial forces. Suppose the particle is at rest at point B at latitude λ on earth’s surface. Note that it is located at a radial distance (Re cos λ) from origin O’ of the frame with axes (OX’, OY’) rotating about the axis O’ N. Hence there acts a centrifugal force on particle along the direction O’ B given by the above equation.
Fcen = m ω2 (Re cos λ) (i)
where, ω is angular velocity of earth’s rotation. Since, particle is at rest relative to earth, there is no coriolis force acting on it.
Thus, for an observer on earth, the particle is subjected to two forces: Fg and Fcen. The resultant of these two forces would not be radially towards O, the center of earth. We usually resolve Fcen into two components: the radial component Fcen cos λ along OB and the component Fcen sin λ tangential to surface of earth. Thus,
Fr’ = Fg – Fcen cos λ
= m (g – ω2 Re cos2 λ) (ii)
and, Ft’ = Fcen sin λ = m ω2 Re cos λ sin λ (iii)
The resultant radial force is sometimes written as mg’, where g’ denotes the ‘effective’ acceleration due to gravity, i.e. g modified by centrifugal acceleration. We find that g’ depends on λ as,
g’ = g – ω2 Re cos2 λ (iv)
The plumb-line at latitude λ is deflected from radial direction OB by an angle θ given by,
Note that local plumb-line at position B defines the vertical direction there. It is along the direction of plumb-line that the resultant force F’ acts.
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