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A typical example of driven harmonic oscillator is a series LCR circuit in which oscillations are sustained by an alternating emf of frequency ω, ε = ε0 sin ω t. Consider a capacitor C, an inductor L, and a resistor R in series with an emf ε. According to Kirchoff’s law: which is similar to typical forced mechanical oscillator equation: Q = Q0 sin (ω t + Ø) The instantaneous current in the circuit i = dQ/dt corresponds to velocity of mechanical oscillator: i = Q0 ω cos (ω t + Ø) = i0 cos (ω t + Ø) i = i0 sin (ω t + Ø) , θ = Ø + π/2 where, θ now refers to phase difference between current i and emf ε. Note that resistance R in electrical impedance plays the same role as resistive part ‘a’ in mechanical impedance. The reactive part of electrical impedance is X = ω L – 1/C ω The inductive reactance ω L is equivalent to inertia term m ω and capacitative reactance 1/ω C corresponds to elasticity of spring k/ω of mechanical oscillator. Inductance produces inertia while (inverse of) capacitance produces springiness. Power: The instantaneous power input in driven LCR circuit is P ( t ) = εi = ε0 i0 sin ω t sin (ω t + θ) Average power input per cycle is Average power input is maximum when cos θ = 1; that is, power resonance occurs when ω = ωr, such that The Q of the circuit is given by Services: - LCR Circuit Homework | LCR Circuit Homework Help | LCR Circuit Homework Help Services | Live LCR Circuit Homework Help | LCR Circuit Homework Tutors | Online LCR Circuit Homework Help | LCR Circuit Tutors | Online LCR Circuit Tutors | LCR Circuit Homework Services | LCR Circuit
A typical example of driven harmonic oscillator is a series LCR circuit in which oscillations are sustained by an alternating emf of frequency ω, ε = ε0 sin ω t. Consider a capacitor C, an inductor L, and a resistor R in series with an emf ε. According to Kirchoff’s law:
which is similar to typical forced mechanical oscillator equation: Q = Q0 sin (ω t + Ø) The instantaneous current in the circuit i = dQ/dt corresponds to velocity of mechanical oscillator: i = Q0 ω cos (ω t + Ø) = i0 cos (ω t + Ø) i = i0 sin (ω t + Ø) , θ = Ø + π/2 where, θ now refers to phase difference between current i and emf ε. Note that resistance R in electrical impedance plays the same role as resistive part ‘a’ in mechanical impedance. The reactive part of electrical impedance is X = ω L – 1/C ω The inductive reactance ω L is equivalent to inertia term m ω and capacitative reactance 1/ω C corresponds to elasticity of spring k/ω of mechanical oscillator. Inductance produces inertia while (inverse of) capacitance produces springiness. Power: The instantaneous power input in driven LCR circuit is P ( t ) = εi = ε0 i0 sin ω t sin (ω t + θ) Average power input per cycle is Average power input is maximum when cos θ = 1; that is, power resonance occurs when ω = ωr, such that The Q of the circuit is given by
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